Get the answers you need from a community of experts on IDNLearn.com. Our platform is designed to provide accurate and comprehensive answers to any questions you may have.

The sum of the first 15 terms of an arithmetic series
IS 615
Given that
the fifth
term is 53 find the common difference


Sagot :

Answer:

d=4

Step-by-step explanation:

SUM OF 15 terms = 615

T5 = 53

T5 = a+(n-1)d

53 = a + 4d

4d = 53 - a

d = (53-a)/4

S15 = 15/2 (2a+14d) =615

15/2 [2a + 14×(53-a)/4 ]

=15/2 [ 2a +(53×14 - 14a )/4 ]

=15/2 [ (8a +742 - 14a ) /4]

615×8 = 15(-6a +742)

-6a+72=615×8/15 =41

-6a+72=42

-6a = - 72 + 42 = -30

a = 30/6= 5

a = 5

T5 = 5 + 4×d = 53

4d= 53 - 5 = 48

4d=48

d=4

Common difference is 4