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The means of six number = 41

Three numbers are 32 , 31 , 42

other three are a,a,a

What sum of 6 numbers

find value of A?

Sagot :

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[tex] \qquad\huge \rm༆ Answer ༄[/tex]

Let's use the formula to fund mean here ~

[tex] \boxed{ \sf mean = \frac{sum \: of \: all \: terms}{number \: of \: terms} }[/tex]

That is ;

[tex]\qquad \sf  \dashrightarrow \: 41 = \dfrac{32 + 31 + 42 + a + a + a}{6} [/tex]

[tex]\qquad \sf  \dashrightarrow \: (41 \times 6) = 105 + 3a[/tex]

[tex]\qquad \sf  \dashrightarrow \: 246 = 105 + 3a[/tex]

[tex]\qquad \sf  \dashrightarrow \: 3a = 246 - 105[/tex]

[tex]\qquad \sf  \dashrightarrow \: 3a = 141[/tex]

[tex]\qquad \sf  \dashrightarrow \: a = 141 \div 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: a = 47[/tex]

Therefore the value of a is 47

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