Nariahtaylored37idn
Answered

Join IDNLearn.com today and start getting the answers you've been searching for. Our community is here to provide the comprehensive and accurate answers you need to make informed decisions.

A six-sided number cube is rolled 900 times.

How many times is it expected that a number greater than 4 will be rolled?

Sagot :

Nelsonclaire44idn

Answer: Rolling a die and obtaining a number follows a binomial distribution.

Expected value of binomial distribution is

E[X]=np

where n is number of toss and p is probability of obtaining the number.

Therefore here the expected value of obtaining a number 4 is:

E[X]=900∗16=150

Step-by-step explanation:

MrRoyalidn

It is expected that a number greater than 4 will be rolled 300 times

The sample space of a die is:

S = {1,2,3,4,5,6}

The probability of obtaining a number greater than 4 is:

[tex]p = 2/6[/tex]

[tex]p = 1/3[/tex]

In 900 rolls, the expected number of number greater than 4 is:

[tex]E(x) = p *n[/tex]

This gives

[tex]E(x) = 1/3 *900[/tex]

[tex]E(x) =300[/tex]

Hence, it is expected that a number greater than 4 will be rolled 300 times

Read more about expected values at:

https://brainly.com/question/15858152

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.