At IDNLearn.com, find answers to your most pressing questions from experts and enthusiasts alike. Our Q&A platform offers detailed and trustworthy answers to ensure you have the information you need.
Sagot :
V² = U² + 2 a S
Here V = final velocity = 0 of the bullet as it stopped
U = initial velocity before the bullet entered the shoulder = 100 m/s
a = ?
S = distance traveled by bullet under the acceleration/deceleration. = 6 cm
= 0.06 meter
a = (0² - 100²) / 2 * 0.06 = - 83,333 meters/sec² = - 8.333 * 10^4 m/sec²
It is negative as it is a deceleration. Now ,let us calculate the time duration T taken by the bullet to stop after entering the shoulder.
V = u + a t Here, we have V = final velocity = 0. u is 100 m/s a is found above.
So 0 = 100 - 83333 T => T = 100 / 83333 = 1.2 milliseconds
Here V = final velocity = 0 of the bullet as it stopped
U = initial velocity before the bullet entered the shoulder = 100 m/s
a = ?
S = distance traveled by bullet under the acceleration/deceleration. = 6 cm
= 0.06 meter
a = (0² - 100²) / 2 * 0.06 = - 83,333 meters/sec² = - 8.333 * 10^4 m/sec²
It is negative as it is a deceleration. Now ,let us calculate the time duration T taken by the bullet to stop after entering the shoulder.
V = u + a t Here, we have V = final velocity = 0. u is 100 m/s a is found above.
So 0 = 100 - 83333 T => T = 100 / 83333 = 1.2 milliseconds
Since the bullet undergoes uniform acceleration, its average speed while inside
the dog is 1/2 of (initial speed + final speed) = 1/2(100 + 0) = 50 m/s .
It travels 6 cm at that average speed.
Time = (distance) / (speed) = (6 cm) / (50 m/s) = (0.06 m) / (50 m/s) = 0.0012 sec
(1.2 milliseconds) .
the dog is 1/2 of (initial speed + final speed) = 1/2(100 + 0) = 50 m/s .
It travels 6 cm at that average speed.
Time = (distance) / (speed) = (6 cm) / (50 m/s) = (0.06 m) / (50 m/s) = 0.0012 sec
(1.2 milliseconds) .
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.