Answer:
5x/7y^3
Step-by-step explanation:
Something to the power of -1/2 is saying 1 over square-root of that something. Let's pretend x is that something. If we have something like this [tex]x^{-\frac{1}{2} }[/tex], then it can be written like this: [tex]\frac{1}{\sqrt{x}}[/tex].
In our problem, we have the chunk to the -1/2 power. So the reciprocal of the chunk would become [tex]\sqrt{\frac{25x^{2} }{49y^{6}}[/tex]
It's easy to solve now. The square root of the numerator becomes 5x and the denominator becomes 7y^3. The simplified version is [tex]\frac{5x}{7y^\power{3}}[/tex]
