Discover new information and get your questions answered with IDNLearn.com. Find reliable solutions to your questions quickly and easily with help from our experienced experts.

Find the inverse of each function.
1) y = log2 (3x)
2)y=log3(x-1)
3)y=-2log x
4)y=log6(3x)
5)y=log3(x+2)
6)y=log3(5^3)
7)y=6^x+5
9)y=log3 2^x
10)y=3^x -7


Sagot :

The inverse of a function is the opposite of the function

How to determine the inverse functions

1) y = log2 (3x)

Swap the positions of x and y

[tex]x = \log_2(3y)[/tex]

Apply the exponential rule

[tex]2^x = 3y[/tex]

Make y the subject

[tex]y = \frac{2^x}3[/tex]

Hence, the inverse function is: [tex]y = \frac{2^x}3[/tex]

2) y=log3(x-1)

Swap x and y

[tex]x = \log_3(y - 1)[/tex]

Apply exponent rule

[tex]3^x = y - 1[/tex]

Make y the subject

[tex]y = 3^x + 1[/tex]

Hence, the inverse function is: [tex]y = 3^x + 1[/tex]

3) y=-2log x

Swap x and y

[tex]x=-2\log y[/tex]

Divide both sides by -2

[tex]-0.5x=\log y[/tex]

Apply exponent rule

[tex]y = 10^{-0.5x}[/tex]

Hence, the inverse function is: [tex]y = 10^{-0.5x}[/tex]

4) y=log6(3x)

Swap x and y

[tex]x = \log_6(3y)[/tex]

Apply exponent rule

[tex]3y = 6^x[/tex]

Make y the subject

[tex]y = \frac{6^x}{3}[/tex]

Hence, the inverse function is: [tex]y = \frac{6^x}{3}[/tex]

5)y=log3(x+2)

Swap x and y

[tex]x = \log_3(y + 2)[/tex]

Apply exponent rule

[tex]y + 2 = 3^x[/tex]

Make y the subject

[tex]y = 3^x - 2[/tex]

Hence, the inverse function is: [tex]y = 3^x - 2[/tex]

6) y=log3(5^3)

Swap x and y

[tex]x = \log_3(5^3)[/tex]

Hence, the inverse function is: [tex]x = \log_3(5^3)[/tex]

7) y=6^x+5

Swap x and y

[tex]x = 6^y + 5[/tex]

Subtract 5 from both sides

[tex]6^y = x - 5[/tex]

Apply logarithm

[tex]y = \log_6(x - 5)[/tex]

Hence, the inverse function is: [tex]y = \log_6(x - 5)[/tex]

9) y=log3 2^x

Swap x and y

[tex]x = \log_3(2^y)[/tex]

Apply exponent rule

[tex]2^y = 3^x[/tex]

Apply logarithm

[tex]y = \log_2(3^x)[/tex]

Hence, the inverse function is: [tex]y = \log_2(3^x)[/tex]

10) y=3^x -7

Swap x and y

[tex]x = 3^y - 7[/tex]

Add 7 to both sides

[tex]3^y = x + 7[/tex]

Apply logarithm

[tex]y = \log_3(x + 7)[/tex]

Hence, the inverse function is: [tex]y = \log_3(x + 7)[/tex]

Read more about inverse functions at:

https://brainly.com/question/14391067