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According to the described situation, we have that:
- The null hypothesis is [tex]H_0: p < 0.4[/tex]
The decision rule is:
- z < 2.327: Do not reject the null hypothesis.
- z > 2.327: Reject the null hypothesis.
The value of the test statistic is of z = -0.866.
What is the null hypothesis?
The claim is:
"Forty percent or more of those persons who retired from an industrial job before the age of 60 would return to work if a suitable job were available"
At the null hypothesis, we consider that the claim is false, that is, the proportion is of less than 40%, hence:
[tex]H_0: p < 0.4[/tex]
What is the decision rule?
We have a right-tailed test, as we are testing if a proportion is less/greater than a value. Since we are working with a proportion, the z-distribution is used.
Using a z-distribution calculator, the critical value for a right-tailed test with a significance level of 0.01 is of z = 2.327, hence, the decision rule is:
- z < 2.327: Do not reject the null hypothesis.
- z > 2.327: Reject the null hypothesis.
What is the test statistic?
The test statistic is given by:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
In which:
- [tex]\overline{p}[/tex] is the sample proportion.
- p is the proportion tested at the null hypothesis.
- n is the sample size.
In this problem, the parameters are:
[tex]p = 0.4, n = 200, \overline{p} = \frac{74}{200} = 0.37[/tex]
Hence:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z = \frac{0.37 - 0.4}{\sqrt{\frac{0.4(0.6)}{200}}}[/tex]
[tex]z = -0.866[/tex]
The value of the test statistic is of z = -0.866.
You can learn more about hypothesis tests at https://brainly.com/question/16313918
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