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If g(x)=7x²−4x−3 and h(x)=5x²−12x, find (h∘g)(1)


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Answer: See below

Step-by-step explanation:

[tex]h\:\circ \:g=h\left(g\left(x\right)\right)[/tex]

[tex]=5\left(7x^2-4x-3\right)^2-12\left(7x^2-4x-3\right)[/tex]

[tex]=5\left(7x^2-4x-3\right)\left(7x^2-4x-3\right)-12\left(7x^2-4x-3\right)[/tex]

[tex]=245x^4-280x^3-130x^2+120x+45-84x^2+48x+36[/tex]

Simplify:

[tex]=245x^4-280x^3-214x^2+168x+81[/tex]

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