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We have that the the molarity of methanol in the solution is mathematically given as
Morality=7.91mol/l
Question Parameters:
An aqueous solution of methanol (MM = 32.04 g/mol)
A molality of 8.83 m and a density of 1.15 g/mL.
Generally the equation for the is mathematically given as
[tex]Morality=\frac{moles of solute }{mass of the solvent}[/tex]
where
Mass of solution=(100+282.2)
Mass of solution=1289.9
Volume=1289.9/1.15
Volume=1.115L
Therefore
[tex]Morality=\frac{moles of solute }{mass of the solvent}[/tex]
Morality=8.83/1.115
Morality=7.91mol/l
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