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write the quadratic equation in standard form: y=ax^2+bc+c that has the given solutions:
(number 9)

Write The Quadratic Equation In Standard Form Yax2bcc That Has The Given Solutions Number 9 class=

Sagot :

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Answer:

x=-b±√b²-4ac

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2a

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Answer:

x² -3x + 1.5

Explanation:

Here using the formula: [tex]\left[\begin{array}{ccc}x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \end{array}\right][/tex]

we can determine a

2a = 2

a = 1

we can determine b

-b = 3

b = -3

we can determine that b = -3

then using a = 1 , b = -3

find c:

(-3)²-4*1*c = 3

9-4c = 3

-4c = -6

c = 3/2

so the quadratic formula is x² -3x + 1.5

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