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combine gas law: PV/T=k or (P1V1)/T1=(P2T2)/T2
ideal gas law: PV=nRT or (P1V1)/T1=(P2T2)/T2
You have four fixed-volume containers at STP. Container A has 0.5 mol of gas in 11.2 L. Container B has 2 mol of gas in 22.4 L. Container C has 1 mol of gas in 22.4 L. Container D has 2 mol of gas in 11.2 L.

Which containers have equal pressures?


Sagot :

The containers that have equal pressures are Container A and Container C

Gas Laws

From the question, we are to determine which containers have equal pressures.

Using the ideal gas law equation, we will determine the containers that have equal pressures.

From the ideal gas equation, we have

PV = nRT

Where,

P is the pressure

V is the volume

n is the number of moles

R is the gas constant

and T is the temperature

Then,

[tex]P = \frac{nRT}{V}[/tex]

  • Container A

n = 0.5 mole

V = 11.2 L

[tex]P = \frac{0.5 \times RT}{11.2}[/tex]

P = 0.04464RT

  • Container B

n = 2 moles

V = 22.4 L

[tex]P = \frac{2 \times RT}{22.4}[/tex]

P = 0.0892857RT

  • Container C

n = 1 mole

V = 22.4 L

[tex]P = \frac{1\times RT}{22.4}[/tex]

P = 0.04464RT

  • Container D

n = 2 mole

V = 11.2 L

[tex]P = \frac{2 \times RT}{11.2}[/tex]

P = 0.17857RT

From above, we can observe that Container A and Container C have equal pressures. P = 0.04464RT

Hence, the containers that have equal pressures are Container A and Container C.

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Answer:

A and C

Explanation:

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