Get expert advice and community support for all your questions on IDNLearn.com. Find the solutions you need quickly and accurately with help from our knowledgeable community.
Sagot :
There are about 1.27 × 10^23 molecules present in 13.5 g of SO2.
What are molecules?
A molecule is the simplest part of a compound that have independent existence.
Number of moles of sulfur dioxide = 13.5 g/64 g/mol = 0.211 moles
If 1 mole of SO2 contains 6.02 × 10^23 molecules
0.211 moles of SO2 contains 0.211 moles × 6.02 × 10^23 molecules/1 mole
= 1.27 × 10^23 molecules
32 g of sulfur contains 6.02 × 10^23 atoms
x g of sulfur contains 2.23 x 10^23
x = 32 × 2.23 x 10^23 /6.02 × 10^23
x = 11.85 g
6.02 × 10^23 formula units has a mass of AgF = 127 g
x formula units has a mass of = 42.15 g
x = 6.02 × 10^23 × 42.15/127
x = 2 × 10^23 formula units
6.02 × 10^23 formula units of Fe2O3 has a mass of 160 g
8.83 x 10^23 formula units of Fe2O3 has a mass of 8.83 x 10^23 x 160 g/6.02 × 10^23
x = 235 g
Learn more about formula unit: https://brainly.com/question/19293051
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Trust IDNLearn.com for all your queries. We appreciate your visit and hope to assist you again soon.