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In the diagram, ABC is a right - angled triangle.
P is a point on AB
BC = 40m AP = 20 m
ABC = 30 degrees

Find the Length of AC

In The Diagram ABC Is A Right Angled Triangle P Is A Point On AB BC 40m AP 20 M ABC 30 Degrees Find The Length Of AC class=

Sagot :

[tex] \to \rm \sin(30) = \dfrac{AC }{AB}[/tex]

[tex] \\ \\ [/tex]

[tex] \to \rm \sin(30) = \dfrac{AC }{40}[/tex]

[tex] \\ \\ [/tex]

[tex] \to \rm \dfrac{1}{2} = \dfrac{AC }{40 \degree}[/tex]

[tex] \\ \\ [/tex]

[tex] \to \rm \dfrac{40}{2} =AC [/tex]

[tex] \\ \\ [/tex]

[tex] \to \rm \: AC = 20 m[/tex]

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