IDNLearn.com is designed to help you find reliable answers to any question you have. Our community is here to provide the comprehensive and accurate answers you need to make informed decisions.
Sagot :
x= Hadley
y= Parker
z= Greenville
segment xz - 13 = segment zy
segment xz = segment zy + 13
Segment zy = 29 miles
Therefore...
segment xz = 29+ 13
Segment xz= 42
Distance from Hadley to Greenville is 42 miles
y= Parker
z= Greenville
segment xz - 13 = segment zy
segment xz = segment zy + 13
Segment zy = 29 miles
Therefore...
segment xz = 29+ 13
Segment xz= 42
Distance from Hadley to Greenville is 42 miles
Answer: [tex]x=y+13\\or\ x-y=13[/tex]
Here 'x' represents the distance between Hadley and Greenville and 'y' represents the distance between Parker and Greenville.
The distance between Hadley and Greenville =42 miles
Step-by-step explanation:
Let the distance between Hadley and Greenville be x and the distance between Parker and Greenville be y.
Then according to the question,
[tex]x=y+13\\or\ x-y=13[/tex]
If the distance between Parker and Greenville = 29 miles
Then substitute the value of y=29 in the above equation, we get
[tex]x=29+13\\\Rightarrow\ x=42[/tex]
⇒ The distance between Hadley and Greenville =42 miles
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.