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A spinner has two equal sections, one green and one orange. The spinner is spun three times, resulting in the sample space S = {GGG, GGO, GOG, OGG, GOO, OGO, OOG, OOO}. If the random variable X represents the number of times orange, O, is spun, which graph represents the probability distribution? A probability distribution is shown. The probability of 0 is 1; 1 is 3; 2 is 3; 3 is 1. A probability distribution is shown. The probability of 0 is 0. 13; 1 is 0. 38; 2 is 0. 38; 3 is 0. 12. A probability distribution is shown. The probability of 0 is 0. 12; 1 is 0. 25; 2 is 0. 5; 3 is 0. 12. A probability distribution is shown. The probability of 0 is 0. 12; 1 is 0. 5; 2 is 0. 25; 3 is 0. 12.

Sagot :

The probabilities are as follows

[tex]\rm P(X =0) = \dfrac{1}{8} ,\ P(X =1) = \dfrac{3}{8}, \ P(X =2) = \dfrac{3}{8} , \ P(X =3) = \dfrac{1}{8}[/tex]

What is probability?

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

A spinner has two equal sections one green and one orange.

The spinner is spun three times, resulting in the sample space (S) will be

S = {GGG, GGO, GOG, OGG, GOO, OGO, OOG, OOO}.

If the random variable X represents the number of times orange.

X = 0, 1, 2, 3

For X = 0, then the probability of not getting orange will be

[tex]\rm P(X = 0) = \dfrac{1}{8}[/tex]

For X = 1, then the probability of getting one orange only will be

[tex]\rm P(X = 1) = \dfrac{3}{8}[/tex]

For X = 2, then the probability of getting two oranges only will be

[tex]\rm P(X = 2) = \dfrac{3}{8}[/tex]

For X = 3, then the probability of getting oranges only will be

[tex]\rm P(X = 3) = \dfrac{1}{8}[/tex]

More about the probability link is given below.

https://brainly.com/question/795909

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