Answered

Connect with experts and get insightful answers on IDNLearn.com. Get thorough and trustworthy answers to your queries from our extensive network of knowledgeable professionals.

Compute the Limit [tex]\lim_{x \to \infty} \frac{(log(x))^{2} }{x}[/tex]

Sagot :

LammettHashidn

By applying L'Hopital's rule twice,

[tex]\displaystyle \lim_{x\to\infty} \frac{\log^2(x)}{x} = \lim_{x\to\infty} \frac{\frac{2\log(x)}x}1 \\\\ = \lim_{x\to\infty} \frac{2\log(x)}x \\\\ = \lim_{x\to\infty} \frac{\frac2x}1 \\\\ = \lim_{x\to\infty}\frac2x = \boxed{0}[/tex]

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.