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Jefferson's back yard is in the shape of a right triangle. One leg of the
triangle is seven feet longer than the other, with a hypotenuse of 17 feet.
How many feet long is the shorter leg?

Sagot :

940172idn

Answer:

8ft

Step-by-step explanation:

Pythagorean Theorem

[tex]a^2+b^2=c^2\\\\x^2+(x+7)^2=17^2\\x^2+(x+7)(x+7)=17^2\\x^2+(x^2+7x+7x+49)=289\\2x^2+14x+49-289=289-289\\2x^2+14x-240=0\\[/tex]

Use Quadratic Formula to Solve

[tex]\frac{-b+-\sqrt{b^2-4ac} }{2a} \\\frac{-14+-\sqrt{14^2-4(2)(-240)} }{2(2)} \\\frac{-14+-\sqrt{2116} }{4}\\x=\frac{-14+46}{4}, x=\frac{-14-46}{4}\\x=8, -15[/tex]

Ignore negative sign

Shorter side is 8ft and longer one is 15ft

Perezidiana2idn

Answer:

8 ft

Step-by-step explanation:

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