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Adult male heights have a normal probability distribution with a mean of 70 inches and a standard deviation of 4 inches.

What is the probability that a randomly selected male is more than 66 inches tall?

Enter your answer in decimal form, e.g. 0.68, not 68 or 68%.

Sagot :

Razorsharptipidn

Answer: 0.84134

Step-by-step explanation:

We need to find the z-score for the given information first since this will help us find the probability. The formula for this is

Z score = [tex]\frac{x - \mu}{\sigma}[/tex]

We have

[tex]x =[/tex] 66 inches (the raw score)

[tex]\mu =[/tex] 70 inches (the population mean)

[tex]\sigma[/tex] = 4 inches (the standard deviation)

This gives

Z score = [tex]\frac{x - \mu}{\sigma}[/tex] = [tex]\frac{66-70}{4} = -1[/tex]

If you use a calculator, or a Z-score table then P(x > Z) is just P(Z > -1) which gives a probability of 0.84134.

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