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Sagot :
[tex]y = \frac 14x^2[/tex] is less steep than the parent quadratic equation, while [tex]y = 2x^2[/tex] is steeper than the parent quadratic equation
How to determine the equations
The parent equation of a quadratic equation is represented as:
[tex]y = x^2[/tex]
For a function to be steeper or less steep than the parent function must be stretched or compressed by a factor k
So, we have:
[tex]y = (kx)^2[/tex]
If k is greater than 1, then the function would be steeper; else, the function would be less steep.
Assume k = 2, we have:
[tex]y = (2x)^2[/tex]
[tex]y = 2x^2[/tex]
Assume k = 1/2, we have:
[tex]y = (\frac 12x)^2[/tex]
[tex]y = \frac 14x^2[/tex]
Hence, [tex]y = \frac 14x^2[/tex] is less steep than the parent quadratic equation, while [tex]y = 2x^2[/tex] is steeper than the parent quadratic equation
Read more about quadratic equations at:
https://brainly.com/question/11631534
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