Answered

Get personalized answers to your unique questions on IDNLearn.com. Discover comprehensive answers to your questions from our community of knowledgeable experts.

Next, the team wants to explore how it can change the steepness of the curved pit. Identify how the graph of each equation compares with the graph of the parent quadratic equation, y=x^2. Drag the equations to the correct location on the chart. Not all equations will be used

Sagot :

MrRoyalidn

[tex]y = \frac 14x^2[/tex] is less steep than the parent quadratic equation, while [tex]y = 2x^2[/tex] is steeper than the parent quadratic equation

How to determine the equations

The parent equation of a quadratic equation is represented as:

[tex]y = x^2[/tex]

For a function to be steeper or less steep than the parent function must be stretched or compressed by a factor k

So, we have:

[tex]y = (kx)^2[/tex]

If k is greater than 1, then the function would be steeper; else, the function would be less steep.

Assume k = 2, we have:

[tex]y = (2x)^2[/tex]

[tex]y = 2x^2[/tex]

Assume k = 1/2, we have:

[tex]y = (\frac 12x)^2[/tex]

[tex]y = \frac 14x^2[/tex]

Hence, [tex]y = \frac 14x^2[/tex] is less steep than the parent quadratic equation, while [tex]y = 2x^2[/tex] is steeper than the parent quadratic equation

Read more about quadratic equations at:

https://brainly.com/question/11631534

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.