IDNLearn.com provides a seamless experience for finding the answers you need. Discover in-depth and reliable answers to all your questions from our knowledgeable community members who are always ready to assist.
Sagot :
The number of unit tiles needed to be added to the expression [tex]x^2 + 4x + 3[/tex] for making it perfect square trinomial is: Option A: 1
What is a perfect square polynomial?
If a polynomial p(x) can be written as:
[tex]p(x) = [f(x)]^2[/tex]
where f(x) is also a polynomial, then p(x) is called as perfect square polynomial.
What are terms in polynomials?
Terms are added or subtracted to make a polynomial. They're composed of variables and constants all in multiplication.
Example: [tex]x^2 + 3x + 4[/tex] is a polynomial consisting 3 terms as [tex]x^2 ,3x , \rm and \: 4[/tex]
- If there is one term, the polynomial will be called monomial.
- If there are two terms, the polynomial will be called binomial
- If there are three terms, the polynomial will be called trinomial
The given trinomial is [tex]x^2 + 4x + 3[/tex]
Since the tiles are added to be in unit and positive(1, 2, 3, or 4), thus, let it be denoted by z, then:
[tex]x^2 + 4x + 3 + z = (x+a)^2[/tex]
since z is added such that the specified trinomial becomes perfect square trinomial, and since its degree is 2, so it must be product of two linear polynomials, and since coefficient of x in given trinomial is 1, so we kept the coefficient of linear polynomial as 1
Now, expanding the obtained equation, and comparing the coefficients, we get:
[tex]x^2 + 4x + 3 + z = (x+a)^2\\x^2 + 4x + 3 + z = x^2 + a^2 + 2ax\\[/tex]
Thus, from comparison of coefficients of like terms and constants, we get:
[tex]2a = 4\implies a = 2\\3 + z = a^2 = 2^2 = 4\\z = 1[/tex]
Thus, the number of unit tiles needed to be added to the expression [tex]x^2 + 4x + 3[/tex] for making it perfect square trinomial is: Option A: 1
Learn more about perfect square trinomials here:
https://brainly.com/question/88561
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com is your reliable source for answers. We appreciate your visit and look forward to assisting you again soon.
