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HOW CAN YOU MAKE 7,5,6,AND 3 EQUAL 75 USING PARENTHESIS.

Sagot :

[tex](7+5)\times6+3=12\times6+3=72+3=\boxed{75}[/tex]

One possible answer is:

5((7x3)-6).

Explanation:

75 ends in 5, so it is divisible by 5. 75/5 = 15. If we can arrange 7, 6 and 3 some way to make 15, we can use this multiplied by 5.

7x3=21, and 21-6=15; this gives us what we need!

5(21-6) = 75; 21 = 3x7, so 5((3x7)-6).

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