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If the force generated by the car to push it forward is 8,000 N, what can be said about the force opposing the car’s motion?

Sagot :

According to Newton's third law

  • Ever action has a equal and opposite reaction.

So

[tex]\\ \rm\dashrightarrow F_{A}=-F_A[/tex]

  • Hence if applied force is 8000N opposing force is also 8000N

As car is pushed forward so the opposing force is less than 8000N

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