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Quadrilateral A B C D is shown. Sides A D and B C are parallel. Sides A B and C D are congruent. Angle A is 115 degrees.
What is the measure of ADC in quadrilateral ABCD?

45°
65°
115°
135°

Sagot :

  • 65° if parallelogram
  • 115° if trapezoid

Solution to the problem

Since no diagram attached there are two possible options.

Option 1

The quadrilateral is parallelogram.

In this case ∠A and ∠D sum up to 180°, therefore:

  • ∠ADC = 180° - 115° = 65°

Option 2

The quadrilateral is isosceles trapezoid.

In this case ∠A is congruent with ∠D, therefore:

  • ∠ADC = ∠A = 115°

Answer:

115

Step-by-step explanation:

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