The effective current when an AC peak voltage of 18V is applied to a lamp with 4 ohm resistance is 3.18 A.
What is current?
Current is the flow of electrons through a conductor when voltage is applied across the conductor.
Given the peak voltage of 18 V, hence:
[tex]V_{rms}=\frac{Peak\ value}{\sqrt{2} } =\frac{18}{\sqrt{2} } =12.73 V\\\\I_{rms}=\frac{V_{rms}}{resistance } =\frac{12.73}{4 } =3.18 A\\[/tex]
The effective current when an AC peak voltage of 18V is applied to a lamp with 4 ohm resistance is 3.18 A.
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