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To control pollination, pollen-producing flowers are often removed from the top of corn in a process called detasseling. The hourly rates for detasselers in Iowa are roughly normally distributed, with a mean of $12/hr and a standard deviation of $2/hr. What are the z-scores for a detasseler making $13 and $17 an hour? z13 = 0. 9, z17 = 1. 25 z13 = 0. 5, z17 = 1. 25 z13 = 0. 5, z17 = 2. 5.

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ShubhamchouhanvrVTidn

The z-scores for a deta seller making $13 and $17 an hour will be [tex]Z_{13}=0.5 \ \ \ Z_{17}=2.5[/tex]

What is z- value ?

The z-scores give us information about how many standard deviations from the mean the data are. This difference can be negative, if the data are n deviations to the left of the mean, or it can be positive if the data are n deviations to the right of the mean.

To calculate the Z scores, we calculate the difference between the value of the data and the mean and then divide this difference by the standard deviation.

[tex]Z=\dfrac{X-\mu}{\sigma}[/tex]

Where x is the value of the data, μ is the mean and σ is the standard deviation

In this case :

μ = 12 $/h

[tex]\sigma[/tex] = 2 $/h

We need to calculate the Z-scores for x=17 and x=13

[tex]Z_{13}=\dfrac{13-12}{2}=0.5[/tex]

[tex]Z_{17}=\dfrac{17-12}{2}=2.5[/tex]

Thus the z-scores for a deta seller making $13 and $17 an hour will be [tex]Z_{13}=0.5 \ \ \ Z_{17}=2.5[/tex]

To know more about z-Value follow

https://brainly.com/question/25638875

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