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A bicycle tire has a volume of 1. 0 L at 22°C. If the temperature of the tire is increased to 52°C, what is the resulting volume of the tire? Type in your answer using the correct number of significant figures. Use the formula for Charles' Law: V1 T1 = V2 T2 L.

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ShubhamchouhanvrVTidn

The resulting volume of the tire would be 1.1 L

What is Charles's law?

According to this law, the volume of a given gas is directly proportional to its temperature, provided that the pressure remains constant.

The law can be presented mathematically as;  

[tex]\dfrac{V_1}{T_1} =\dfrac{V_2}{T_2}[/tex]

In this case, V1 = 1.0 L, T1 = 22 °C (295 K), T2 = 52 °C (325 K).

[tex]V_2=\dfrac{V_1T_2}{T_1}[/tex]V

[tex]V_2=\dfrac{1\times 325}{295}=1.1\ L[/tex]

                             

Hence the final volume of the tire will be 1.1 L

More on Charles's law can be found here:

brainly.com/question/3491421

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