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OMG I'M HAVING A BRAIN FART AND CAN"T SOLVE THIS FOR THE LIFE OF ME. HELPPPP!

OMG IM HAVING A BRAIN FART AND CANT SOLVE THIS FOR THE LIFE OF ME HELPPPP class=

Sagot :

Answer:

Step-by-step explanation:

Because a square has 4 equal sides:

P = 4x

A = [tex]x^{2}[/tex]

Step 1. Substitute 4x into perimeter equation

[tex]P=\frac{4x^2+4}{x^2-2x+1}[/tex]                              (original P equation)

[tex]4x=\frac{4x^2+4}{x^2-2x+1}[/tex]                             (substitute P = 4x)

Step 2. Solve for x

[tex]4x(x^2-2x+1)={4x^2+4}[/tex]         (multiply denominator on both sides)

[tex]4x^3-8x^2+4x={4x^2+4}[/tex]          (distribute 4x)

[tex]4x^3-12x^2+4x-4=0[/tex]            (combine like terms, set = to 0)

[tex]4(x^3-3x^2+x-1)=0[/tex]             (factor)

Continue using quadratic formula to find x

Step 3. Plug x into area equation, [tex]x^{2}[/tex]

Hope this helps! Cannot finish answer right now, so sorry

side=Perimeter/4

side:-

[tex]\\ \rm\Rrightarrow \dfrac{4(x^2+1)}{4(x^2-2x+19}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{x^2+1}{x^2-2x+19)}✓/tex]

Area=side ²

[tex]\\ \rm\Rrightarrow \left(\dfrac{x^2+1}{x^2-2x+19}\right)^2[/tex]

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