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The area of parallelogram is 104 square units and base length is 13. What is the height of the parallelogram?

Sagot :

Answer :

  • 8 units

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Step-by-step explanation :

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Here,

  • Area of the parallelogram is 104 sq. units

  • Base length of the parallelogram is 13 units.

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We know that,

[tex]{\longrightarrow \qquad{ \mathfrak{ \pmb{Base \times Height = Area_{(Parallelogram)}}}}}[/tex]

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Now, Substituting the values in the formula :

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[tex]{\longrightarrow \qquad{ \sf{ {13 \times Height = 104}}}}[/tex]

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[tex]{\longrightarrow \qquad{ \sf{ {Height = \dfrac{104}{13} }}}}

[/tex]

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[tex]{\longrightarrow \qquad{ \pmb { \frak{Height \: \: {= 8}}}}}[/tex]

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Therefore,

  • The Height of the parallelogram is 8 units.
TheAestheticBoyidn

Question :-

  • The Area of Parallelogram is 104 units² . Its Base is 13 units . What is the Height of the Parallelogram ?

Answer :-

  • Height of Parallelogram is 8 units .

Explanation :-

As per the provided information in the given question, we have been given that the Area of Parallelogram is 104 units² . Its Base is given as 13 units . And, we have been asked to calculate the Height of the Parallelogram .

For calculating the Height , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed{ \sf{ \: Area \: _{Parallelogram} \: = \: Base \: \times \: Height \: }} [/tex]

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf { Area \: _{Parallelogram} \: = \: Base \: \times \: Height } [/tex]

[tex] \longmapsto \: \: \: \sf { 104 \: = \: 13 \: \times \: Height } [/tex]

[tex] \longmapsto \: \: \: \sf { \dfrac {104}{13} \: = \: Height} [/tex]

[tex] \longmapsto \: \: \: \sf { 8 \: = \: Height} [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Height \: = \: 8 }} [/tex]

Hence :-

  • Height of Parallelogram = 8 units .

[tex] \underline {\rule {204pt} {4pt}} [/tex]

Additional Information :-

[tex] \begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} \end{gathered} \end{gathered} [/tex]

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