Answered

Get clear, concise, and accurate answers to your questions on IDNLearn.com. Ask your questions and receive detailed and reliable answers from our experienced and knowledgeable community members.

3. Calculate the [H+], POH, and [OH-] for the following solutions:

a) (10 Points) pH 2. 90 (the approximate pH of lemon juice

b) (10 Points) pH 3. 86 (the approximate pH of sauerkraut)

c) (10 Points) pH 10. 81 (the approximate pH of milk of magnesia)

d) (10 Points) pH 4. 11 (the approximate pH of orange juice)

e) (10 Points) pH 11. 61 (the approximate pH of household ammonia)

Sagot :

Pstnonsonjokuidn

The  pH refers to the negative logarithm of the hydrogen ion concentration of a solution.

What is pH?

The term pH refers to the negative logarithm of the hydrogen ion concentration of a solution. Let us now solve each question.

a) Since pH = 2.90

[H^+] = Antilog(-2.90) = 1.26 * 10^-3 M

[OH^-] = 1 * 10^-14/ 1.26 * 10^-3 = 7.9 * 10^-12 M

pOH = 14 - 2.90 = 11.1

b) Since pH = 3. 86

[H^+] = Antilog(-3.86) = 1.38 * 10^-4 M

[OH^-] = 1 * 10^-14/ 1.38 * 10^-4 = 7.2 * 10^-11 M

pOH =  14 - 3.86 = 10.14

c)Since pH = 10.81

[H^+] = Antilog(-10.81) = 1.55 * 10^-11 M

[OH^-] = 1 * 10^-14/ 1.55 * 10^-11 = 6.5 * 10^-4 M

pOH = 14 -  10.81 = 3.19

d) Since pH = 4.11

[H^+] = Antilog(-4.11) = 7.8 * 10^-5 M

[OH^-] = 1 * 10^-14/7.8 * 10^-5 = 1.3 * 10^-10M

pOH = 14 - 4.11 = 9.89

e) Since pH = 11.61

[H^+] = Antilog(-11.61) =2.45 * 10^-12 M

[OH^-] = 1 * 10^-14/2.45 * 10^-12 = 4.1 * 10^-3 M

pOH = 14 - 11.61 = 2.39

Learn more about pH:https://brainly.com/question/15289741

#SPJ1

Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.