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What is the equation of the quadratic function with a vertex at (2,–25) and an x-intercept at (7,0)? f(x) = (x – 2)(x – 7) f(x) = (x 2)(x 7) f(x) = (x – 3)(x 7) f(x) = (x 3)(x – 7)

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The quadratic equation with the given characteristics is:

f(x) = (x + 3)*(x - 7).

How to get the quadratic equation?

We know that the vertex must be (2, -25) and it passes through (7, 0).

For a quadratic equation:

y = a*x^2 + b*x +c

The x-value of the vertex is:

x = -b/2a

Then we have:

2 = -b/2a

We also have:

-25 = a*4 + b*2 + c

And because the function passes through (7, 0) we know that 7 is one of the roots, then:

0 = a*49 + b*7 + c

Then we have 3 equations to work with:

2 = -b/2a

-25 = a*4 + b*2 + c

0 = a*49 + b*7 + c

If we subtract the third and second equations we get:

25 = a*45 + b*5

Now, with the first equation we can rewrite:

a  = -b/4

Replacing that in the other equation:

25 = a*45 + b*5

25 = (-b/4)*45 + b*5 = b*(-25/4)

25*(-4/25) =b = -4

Now we know the value of b.

2 = -(-4)/2a

a = 1

Now we need to find the value of c, we have that:

0 = 1*49 + -4*7 + c

0 = 49 - 28 + c

0 = 21 + c

Then c = -21

The equation is:

[tex]y = x^2 - 4x - 21[/tex]

It can be factorized to:

f(x) = (x + 3)*(x - 7).

If you want to learn more about quadratic equations:

https://brainly.com/question/1214333

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