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Khamisi and Harut wrote down two different functions that have the same rate of change. Khamisi's function is represented by the table shown below. x y -1 -5 1 -1 3 3 Write an equation, in slope intercept form, that could be Harut's function.

Sagot :

The equation of line is x+2y+3=0.

What is a equation of the line?

The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables, and c is the constant term. It is an equation of degree one, with variables x and y.

Given:

x:-1  -5  1

y:-1  3  3

So,

m= 3-1/-5-(-1)

m= 2/-4

m=-1/2

Now, equation of line

(y-(-1))= m (x-(-1))

y+1= -1/2(x+1)

2y+2=-x-1

x+2y+3=0

Hence, the equation of line is x+2y+3=0.

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