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(b) The pressure of the helium in the balloon is 100 000 Pa.
The volume of the balloon is 0.030 m².
The balloon is compressed at a constant temperature causing the volume to
decrease to 0.025 m².
No helium leaves the balloon.
Calculate the new pressure in the balloon

Sagot :

CintiaSalazaridn

Taking into account the Boyle's law, the new pressure in the balloon is 120 000 Pa.

What is Boyle's law

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Mathematically, this law says that if the amount of gas and the temperature remain constant, the product of pressure times volume always has the same value:

P×V= k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following is true:

P1×V1=P2×V2

New pressure in the ballon

In this case, you know:

  • P1= 100 000 Pa
  • V1= 0.030 m²
  • P2= ?
  • V2= 0.025 M²

Replacing in the Boyle's law:

100 000 Pa×0.030 m² =P2×0.025 m²

Solving:

(100 000 Pa×0.030 m²) ÷0.025 m²= P2

120 000 Pa= P2

Finally, the new pressure in the balloon is 120 000 Pa.

Learn more about Boyle's law:

https://brainly.com/question/4147359

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