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Sagot :
Answer + Step-by-step explanation:
x² + 4x + 29 = 0
⇔ [x² + 4x] + 29 = 0
⇔ [x² + 4x + 4 - 4] + 29 = 0 (just add and subtract 4)
⇔ [x² + 4x + 4] - 4 + 29 = 0
⇔ (x + 2)² - 4 + 29 = 0 (Replace x² + 4x + 4 by (x + 2)²)
⇔ (x + 2)² + 25 = 0
⇔ (x + 2)² = -25 impossible because (x + 2)² > 0 and -25 < 0
Then there is no solution to the quadratic.
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