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Answer:

[tex]sin\theta=\dfrac{1}{2}[/tex]

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Given

  • [tex]cos \theta=\dfrac{\sqrt{3} }{2}[/tex]

To find

  • The value of [tex]sin\theta[/tex]

Solution

Use identity [tex]sin^2\theta+cos^2\theta=1[/tex] :

  • [tex]sin^2\theta=1-cos^2\theta[/tex]
  • [tex]sin^2\theta=1-(\dfrac{\sqrt{3} }{2} )^2[/tex]
  • [tex]sin^2\theta=1-\dfrac{{3} }{4}[/tex]
  • [tex]sin^2\theta=\dfrac{{1} }{4}[/tex]
  • [tex]sin\theta=\sqrt{\dfrac{{1} }{4} }[/tex]
  • [tex]sin\theta={\dfrac{{1} }{2} }[/tex]
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