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The perimeter of a square is 32 feet. Find the length of one of the diagonals

The Perimeter Of A Square Is 32 Feet Find The Length Of One Of The Diagonals class=

Sagot :

32/4 is 8, so we know that the lengths of the sides are 8 feet.

Because of this I can safely say that the diagonal of the square is 8√2 feet long.

Here's my proof:

[tex]c=\sqrt { { 8 }^{ 2 }+{ 8 }^{ 2 } } \\ \\ =\sqrt { 64+64 } \\ \\ =\sqrt { 64\cdot 2 } \\ \\ =\sqrt { 64 } \sqrt { 2 } \\ \\ =8\sqrt { 2 } [/tex]
The length it's 8 feet .
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