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If the molar mass of na2so4•nh2o is 304.04 g/mol, what is the hydration number 'n'?

Sagot :

Hydration number is 9

Given:

molar mass of na2so4•nh2o = 304.04 g/mol

To Find:

hydration number 'n'

Solution: hydration number is the number of molecules of water with which an ion can combine in an aqueous solution of given concentration.

Atomic mass of Na = 23g

S = 32g

0 = 16g

H = 1g

Molar mass of the compound is evaluated as:

2(23) +32 + 4(16) + n[2(1) +16] = 304.04

46 +32 +64 +18n = 304.04

142 +18n = 304.04

18n = 304.04 - 142

18n = 162.04

n = 9

So, hydration number is 9

Learn more about Hydration number here:

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