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Side a of a triangle is 4 cm longer than side b. Side c is twice as long as side b. What is the length of each side if the perimeter is 28 cm?
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Sagot :

Konrad509idn
[tex]a=b+4\\ c=2b\\ a+b+c=28\\\\ b+4+b+2b=28\\ 4b=24\\ b=6\\\\ a=6+4\\ a=10\\\\ c=2\cdot6\\ c=12\\\\ \boxed{a=10,b=6,c=12} [/tex]

Side a, b and c are 10cm , 6cm , 12cm

Given that;

Side a = 4 + Side b

Side c = 2(Side b)

Perimeter of triangle = 28 cm

Find:

Length of each side

Computation:

Assume;

Side b = q

Side a = 4 + q

Side c = 2q

So,

Perimeter of triangle = 28 cm

q + 4 + q + 2q = 28

4q = 24

q = 6

Side a = 10 cm

Side b = 6 cm

Side c = 12 cm

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