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If a circle has equation (x-3)^2 + (y+1)^2 = 49, what is it’s domain?
I’m forgetting everything from algebra

Sagot :

MrRoyalidn

The domain of the circle is [-4, 10]

How to determine the domain of the circle?

The circle equation is given as:

(x - 3)^2 + (y + 1)^2 = 49

Express 49 as 7^2

So, we have

(x - 3)^2 + (y + 1)^2 = 7^2

The general circle equation is

(x - a)^2 + (y - b)^2 = r^2

Where the domain is

Domain = [a ± r]

So, we have

Domain = [3 ± 7]

Evaluate

Domain = [3 - 7, 3 + 7]

This gives

Domain = [-4, 10]

Hence, the domain of the circle is [-4, 10]

Read more about domain at:

https://brainly.com/question/2264373

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