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Sagot :
The expression for the area of a rectangle is [tex]2x^3-7x^2+6x-2[/tex].
It is given in the question that the length of the rectangle is [tex]2x^2-3x+1[/tex] and width is (x - 2).
We have to find a expression for the area of a rectangle.
We know that,
Area of a rectangle = l * b
Where,
l represents the length of the rectangle
b represents the breadth of the rectangle
Hence, using the data given in the question, we can write,
Area of a rectangle = [tex](2x^2-3x+1)*(x-2)[/tex]
Area of a rectangle = [tex](2x^3)+(-4x^2)+(-3x^2)+(6x)+(-2)[/tex]
Area of a rectangle = [tex]2x^3-7x^2+6x-2[/tex]
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