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The heat capacity of the calorimeter is 16.8 J/K.
Now we know that the calorimeter is a device from which there is no heat loss or gain. In this case, the heat lost by the hot water is equal to the heat gained by the calorimeter.
Thus;
cwθ = ccθ
Where;
cc= heat capacity of the calorimeter
cw = heat capacity of water
θ == temperature change
Hence;
4.2 * (37 - 25) = cc (25 - 22)
cc = 4.2 * (37 - 25)/(25 - 22)
cc = 16.8 J/K
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