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Sagot :
3x - y = 42x + y = 6the answer is always:y = 3x 4y = 6-2xand y = y gives:3x-4 = 6-2x, which gives:5x = 10x = 2
The x-coordinates and y-coordinates of the given simultaneous equations are; as silver below.
How to solve simultaneous equations?
1) To use linear combinations to solve the simultaneous equation;
3x – y = 4 ------(eq 1)
2x + y = 6 ---- (eq 2)
Add eq 1 to eq 2 to get;
5x = 10
divide both sides by 2 to get;
x = 2
Thus; 3(2) - y = 4
y = 6 - 4
y = 2
2) 5x - y = 25 ------(eq 1)
4x + 3y = 1 ----- (eq 2)
Make y the subject in eq 1 t get;
y = 5x - 25
Put 5x - 25 for y into the equation 2 to get;
4x + 3(5x - 25) = 1
4x + 15x = 76
19x = 76
x = 4
y = 5(4) - 25
y = -5
3) x = y + 16 - - - (eq 1)
y + 4x = 9 - - - (eq 2)
Put eq 1 in eq 2 to get;
y + 4(y + 16) = 9
y + 4y + 64 = 9
5y + 64 = 9
y = (9 - 64)/5
y = -11
Thus;
x = -11 + 16
x = 5
4) -6x - 7y = 8 - - - (eq 1)
x + 5y = 11 - - - (eq 2)
Make x the subject in eq 2 to get;
x = 11 - 5y
Put 11 - 5y for x in eq 1;
6(11-5y) -7y = 8
66 + 30y - 7y = 8
23y = -58
y = -2.5217
Thus;
x + 5(-2.5217) = 8
x = 8 + 12.608
x = 20.608
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