Connect with knowledgeable individuals and get your questions answered on IDNLearn.com. Our experts provide timely, comprehensive responses to ensure you have the information you need.

A speed skater goes around a turn that has a radius of 27 m. The skater has a speed of 12 m/s and experiences a centripetal force of 450 N. What is the mass of the skater?

Sagot :

ANSWER

m = 84.375 kg

EXPLANATION

Given:

• The radius of the circular path, r = 27m

,

• The tangential speed of the skater, v = 12m/s

,

• The centripetal force the skater experiences, Fc = 450N

Unknown:

• The mass of the skater, m

The centripetal force an object of mass m experiences while moving through a circular path of radius r, with a tangential speed v is,

[tex]F_c=m\cdot\frac{v^2}{r}[/tex]

To solve for m, divide both sides by v² and multiply both sides by r,

[tex]m=F_c\cdot\frac{r}{v^2}[/tex]

Replace with the given values,

[tex]m=450N\cdot\frac{27m}{12^2m^2/s^2}=450\operatorname{kg}\cdot m/s^2\cdot\frac{3}{16}s^2/m=84.375\operatorname{kg}[/tex]

Hence, the mass of the skater is 84.375 kilograms.

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.