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Sagot :
The general equation of line with slope m, and passing points (a, b) is :
y = m (x - a) + b
In the given equation,
The slope is 1/2 : m = 1/2
through a point (-2,-5) : (a, b) = (-2, -5)
Substitute the value and put it in the general equation of line
[tex]\begin{gathered} y=m(x-a)+b \\ y=\frac{1}{2}(x-(-2))+(-5) \\ y=\frac{1}{2}(x+2)-5 \\ y=\frac{x}{2}+\frac{2}{2}-5 \\ y=\frac{x}{2}+1-5 \\ y=\frac{x}{2}-4 \\ y=\frac{x-8}{2} \\ 2y=x-8 \\ x-2y=8 \end{gathered}[/tex]Equation of line : x - 2y = 8
Answer : x - 2y = 8
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