Engage with knowledgeable experts and get accurate answers on IDNLearn.com. Our platform offers comprehensive and accurate responses to help you make informed decisions on any topic.
we have that
the radius is
r=12.1 in
the volume of a sphere is
[tex]V=\frac{4}{3}\cdot\pi\cdot r^3[/tex]substitute the given values
[tex]\begin{gathered} V=\frac{4}{3}\cdot3.14\cdot12.1^3 \\ \\ V=7,416.94\text{ in3} \end{gathered}[/tex]Part 2
In this problem we have the diameter of the sphere
D=13.6 mm
so
r=D/2=13.6/2=6.8 in
substitute in the formula
[tex]\begin{gathered} V=\frac{4}{3}\cdot3.14\cdot6.8^3 \\ V=1,316.42\text{ in3} \end{gathered}[/tex]