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Sagot :
Solution:
Given that the area of circle Q is;
[tex]A=169\pi in^2[/tex]Also, the general formula is;
[tex]\begin{gathered} A=\pi r^2 \\ \\ \text{ Where }r=radius \end{gathered}[/tex]Thus, the radius, r, of the circle is;
[tex]\begin{gathered} 169\pi=\pi r^2 \\ \\ r^2=169 \\ \\ r=\sqrt{169} \\ \\ r=13in \end{gathered}[/tex]Thus, the diameter, d, is;
[tex]\begin{gathered} d=2r \\ \\ d=2(13in) \\ \\ d=26in \end{gathered}[/tex]ANSWER: The diameter of the circle is 26in
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