The system of equations we have is:
[tex]\begin{gathered} -3x-2y=-7 \\ x+4y=1 \end{gathered}[/tex]And we need to check if the point (3,-1) is a solution.
Step 1. Identify the values of x and y from the point.
In a point, the first number represents the x-value, and the second number represents the y-value. So in point (3,-1) 3 is the x-value, and -1 is the y-value:
[tex]\begin{gathered} x=3 \\ y=-1 \end{gathered}[/tex]Step 2. Substitute the x and y-value into the first equation and check that the result is equal to -7.
The first equation is:
[tex]-3x-2y=-7[/tex]Substituting x=3 and y=-1:
[tex]-3(3)-2(-1)=[/tex]Solve the operations:
[tex]-9+2=-7[/tex]Since we get -7 as the result, (3,-1) is a solution for the first equation. But we still need to check if the point is a solution for the second equation.
Step 3. Substitute the x and y values into the second equation and check that the result is 1.
The second equation of the system is:
[tex]x+4y=1[/tex]Substituting x=3 and y=-1:
[tex]3+4(-1)=[/tex]Solving the operations:
[tex]3-4=-1[/tex]The result we get is -1, not 1. Thus, since the point (3,-1) is not a solution for the second equation, it is also not a solution to the system of equation.
Answer: False