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Sagot :
2005= 18,000
2010= 45,000
1) make 2005 year "0", and 2010 year "5"
2)in order to solve this problem and figure out the rate of change, we must use the equation for exponential functions y=ab^x
3) a= the y- value of y intercept ( what does y equal when x is zero) in this case a population number so, a= 18,000; b= the unknown rate of change; x= time and since we're finding b we can plug in 5 for the time in years; y= the value of y in terms of the x-value, so when x is 5, y is 45,000
4) you end up with something like this
45,000= 18,000b^5
5) in order to proceed to solve you must get b alone
6) divide both sides by 18,000
7) so you no have 2.5= b^5
8) take the fifth root of both sides
9) now you have your answer b=1.20112443398
2010= 45,000
1) make 2005 year "0", and 2010 year "5"
2)in order to solve this problem and figure out the rate of change, we must use the equation for exponential functions y=ab^x
3) a= the y- value of y intercept ( what does y equal when x is zero) in this case a population number so, a= 18,000; b= the unknown rate of change; x= time and since we're finding b we can plug in 5 for the time in years; y= the value of y in terms of the x-value, so when x is 5, y is 45,000
4) you end up with something like this
45,000= 18,000b^5
5) in order to proceed to solve you must get b alone
6) divide both sides by 18,000
7) so you no have 2.5= b^5
8) take the fifth root of both sides
9) now you have your answer b=1.20112443398
Answer:It's 112,500
Step-by-step explanation:
The step by step would be that
y=a * b
p(x)=18000*b^x
45,000=18,000*b^x
45000 18000*b^1 <dividing
18000 18000 <dividing
b=2.5
p(x)=18000*2.5^x
p(2)=18000*2.5^2=112,500
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