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What is the probability of drawing four cards from a standard deck and them all being aces?

Sagot :

We start by saying that the deck has 52 cards, in which they have 4 aces (one for each suit).

We are also taking about drawing cards wthout replacement.

Then, for the first draw, we have 4 in 52 chances of drawing an ace.

For the second draw, as one ace is taken out of the deck of cards, there is a chance of 4-1=3 out of 52-1=51 of drawing an ace.

This can be generalized for the 4 draws as:

[tex]P=\frac{4}{52}\cdot\frac{3}{51}\cdot\frac{2}{50}\cdot\frac{1}{49}=\frac{24}{6,497,400}=3.7\cdot10^{-6}[/tex]

where P is the probability of drawing 4 aces in 4 draws.

There is a probability of 3.7 * 10^(-6) = 0.0000037 = 0.00037% of drawing 4 cards from a standard deck and all 4 being aces.

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