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Theequation ^4 +^3 −−1=0a. Has four unequal complex rootsb. Has two equal real roots and two equal complex rootsc. Has two unequal real roots and two unequal complex rootsd. Has one real root of multiplicity 2 and a second real root of multiplicity 2e. Is not solvable

Sagot :

Answer:

Alternative C - Has two unequal real roots and two unequal complex roots

Step-by-step explanation:

The roots of this equation are:

(solved using the computer):

[tex]1,\text{ -1, }\frac{1-i\sqrt[]{3}}{2},\text{ }\frac{1+i\sqrt[]{3}}{2}[/tex]

As we can see, we have two unequal real roots and two unequal complex roots.

Alternative C.

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