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write the equation of the line, with the given properties, in slope-intercept form.Slope=-6, through (-8,8)

Sagot :

The given slope is:

[tex]m=-6[/tex]

And the point:

[tex](-8,8)[/tex]

we label the coordinates as follows:

[tex]\begin{gathered} x_1=-8 \\ y_1=8 \end{gathered}[/tex]

And now, we use the slope-point formula, which is:

[tex]y-y_1=m(x-x_1)[/tex]

substituting the known values of slope m and the point:

[tex]y-8=-6(x-(-8))[/tex]

We need to solve this for y to find the slope intercept form (which is y=mx+b):

[tex]\begin{gathered} y-8=-6(x+8) \\ y-8=-6x-48 \\ y=-6x-48+8 \\ y=-6x-40 \end{gathered}[/tex]

The slope-intercept form is:

y = -6x - 40

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